Circle Properties (Part 1) | Angles,Arcs & Chords

Synopsis

This article covers the essential skills of circle properties – a core topic in DSE Paper 1 Section A(2) and Section B worth 4–7 marks. You will learn the basic definitions of circle elements (centre, radius, chord, arc, sector), the relationships between central angles, arcs, and chords, the inscribed angle theorem, the properties of cyclic quadrilaterals, and how to apply these theorems in geometric proofs. The article includes step-by-step worked examples, DSE exam techniques, practice questions. These are essential skills that appear regularly in DSE papers.


Learning Objectives

By the end of this article, you should be able to:

  • Define key circle elements: centre, radius, chord, arc, sector, tangent.
  • Apply the relationship between central angles, arcs, and chords (equal central angles → equal arcs → equal chords).
  • Apply the inscribed angle theorem and its corollaries.
  • Apply the angle in a semicircle theorem (angle subtended by a diameter is 90°).
  • Apply the properties of cyclic quadrilaterals (opposite angles supplementary, exterior angle theorem).
  • Solve DSE-style geometry problems using circle properties.

1. Introduction:

Circle geometry appears every year in DSE Paper 1 Section A(2) and Section B. Questions may ask you to:

  • Find unknown angles or lengths using circle theorems
  • Prove geometric relationships using circle properties
  • Apply cyclic quadrilateral properties
  • Solve multi-step geometry problems involving circles

These are essential skills that also appear in more advanced geometry topics.

DSE Exam Tip

Circle property questions often appear in Section A(2) as short-answer questions worth 3–4 marks, and in Section B as longer proof questions worth 5–7 marks.

2. Basic Definitions

A circle is a set of points equidistant from a fixed point called the centre. Key elements include:

  • Radius: Distance from centre to any point on the circle.
  • Chord: A line segment with endpoints on the circle.
  • Diameter: A chord passing through the centre (longest chord).
  • Arc: A portion of the circumference.
  • Sector: A region bounded by two radii and an arc.
  • Central angle: An angle whose vertex is at the centre.
  • Inscribed angle: An angle whose vertex is on the circle.

3. Central Angles, Arcs and Chords

In the same circle or equal circles:

  • Equal central angles subtend equal arcs.
  • Equal arcs subtend equal chords.
  • Equal chords subtend equal central angles.

Worked Example

Question: In a circle, central angle \( \angle AOB = 60^\circ \). Find the measure of arc \( AB \).

Solution

The measure of an arc is equal to its central angle.

Answer: Arc \( AB = 60^\circ \).

4. Inscribed Angle Theorem

The inscribed angle theorem states:

  • An inscribed angle is half the measure of its intercepted arc.
  • Inscribed angles that intercept the same arc are equal.

Worked Example

Question: In the figure, \( \angle ABC = 40^\circ \). What is the measure of arc \( AC \)?

Solution

By the inscribed angle theorem, \( \angle ABC = \frac{1}{2} \times \text{arc } AC \).

So \( 40^\circ = \frac{1}{2} \times \text{arc } AC \)\( \text{arc } AC = 80^\circ \).

Answer: Arc \( AC = 80^\circ \).

5. Angle in a Semicircle

Theorem: An angle inscribed in a semicircle is a right angle (90°). That is, if \( AB \) is a diameter and \( C \) is on the circle, then \( \angle ACB = 90^\circ \).

Worked Example

Question: \( AB \) is a diameter of a circle. Point \( C \) is on the circle. If \( \angle CAB = 35^\circ \), find \( \angle ABC \).

Solution

Since \( AB \) is a diameter, \( \angle ACB = 90^\circ \).

In triangle \( ABC \), \( 35^\circ + 90^\circ + \angle ABC = 180^\circ \).

\( \angle ABC = 180^\circ - 125^\circ = 55^\circ \).

Answer: \( \angle ABC = 55^\circ \).

6. Cyclic Quadrilaterals

A cyclic quadrilateral is a quadrilateral whose vertices all lie on a circle. Key properties:

  • Opposite angles are supplementary: \( \angle A + \angle C = 180^\circ \), \( \angle B + \angle D = 180^\circ \).
  • An exterior angle of a cyclic quadrilateral equals the opposite interior angle.

Worked Example

Question: In cyclic quadrilateral \( ABCD \), \( \angle A = 70^\circ \) and \( \angle C = 110^\circ \). Is this possible? Explain.

Solution

In a cyclic quadrilateral, opposite angles are supplementary.

\( \angle A + \angle C = 70^\circ + 110^\circ = 180^\circ \)

Answer: Yes, this is possible since opposite angles sum to 180°.

7. Worked Examples

Example 1: Inscribed Angles

Question: In the figure, \( O \) is the centre of the circle. \( \angle AOB = 100^\circ \). Find \( \angle ACB \).

Solution

\( \angle ACB \) is an inscribed angle intercepting arc \( AB \).

The central angle \( \angle AOB = 100^\circ \) intercepts the same arc.

By the inscribed angle theorem: \( \angle ACB = \frac{1}{2} \times 100^\circ = 50^\circ \).

Answer: \( 50^\circ \).

Example 2: Cyclic Quadrilateral

Question: In cyclic quadrilateral \( ABCD \), \( \angle A = 3x \) and \( \angle C = 2x + 20^\circ \). Find \( x \).

Solution

Opposite angles in a cyclic quadrilateral are supplementary.

\( 3x + (2x + 20^\circ) = 180^\circ \)

\( 5x + 20^\circ = 180^\circ \)

\( 5x = 160^\circ \)\( x = 32^\circ \).

Answer: \( x = 32^\circ \).

Example 3: Multi-Step Proof

Question: Prove that if \( ABCD \) is a cyclic quadrilateral, then \( \angle ABD = \angle ACD \).

Solution

In a cyclic quadrilateral, all four vertices lie on the same circle.

\( \angle ABD \) and \( \angle ACD \) are both inscribed angles that intercept the same arc \( AD \).

Inscribed angles intercepting the same arc are equal.

Answer: \( \angle ABD = \angle ACD \) (proved).

8. DSE-Style Practice Questions

Section A(2) & Section B Style

Question 1 MC
In a circle, central angle \( \angle AOB = 80^\circ \). What is the measure of arc \( AB \)?
A. \( 40^\circ \)     B. \( 80^\circ \)     C. \( 160^\circ \)     D. \( 280^\circ \)

Question 2 MC
In the figure, \( O \) is the centre. \( \angle ABC = 35^\circ \). Find \( \angle AOC \).
A. \( 35^\circ \)     B. \( 70^\circ \)     C. \( 17.5^\circ \)     D. \( 105^\circ \)

Question 3 Short Answer
In cyclic quadrilateral \( ABCD \), \( \angle A = 85^\circ \). Find \( \angle C \).

Question 4 Short Answer
\( AB \) is a diameter. \( C \) is on the circle. If \( \angle BAC = 28^\circ \), find \( \angle ABC \).

Question 5 MC
Which of the following is not a property of a cyclic quadrilateral?
A. Opposite angles are supplementary
B. Exterior angle equals opposite interior angle
C. All angles are equal
D. Vertices lie on a circle

9. Solutions with Explanations

Question 1: B. \( 80^\circ \)
The measure of an arc is equal to its central angle.
Question 2: B. \( 70^\circ \)
\( \angle ABC \) is an inscribed angle intercepting arc \( AC \), so central angle \( \angle AOC = 2 \times 35^\circ = 70^\circ \).
Question 3: \( 95^\circ \)
Opposite angles in a cyclic quadrilateral are supplementary: \( 85^\circ + \angle C = 180^\circ \)\( \angle C = 95^\circ \).
Question 4: \( 62^\circ \)
Since \( AB \) is a diameter, \( \angle ACB = 90^\circ \). Then \( 28^\circ + 90^\circ + \angle ABC = 180^\circ \)\( \angle ABC = 62^\circ \).
Question 5: C. All angles are equal
In a cyclic quadrilateral, only opposite angles are supplementary, not all equal.

9. Exercise

Click the following link to have
 An Exercise on Circle Properties (Part 1) | Angles,Arcs & Chords

Key Takeaways

What You Should Remember
  • Central angle = arc measure.
  • Inscribed angle = half its intercepted arc.
  • Angle in a semicircle = 90° (diameter → right angle).
  • Cyclic quadrilateral: Opposite angles are supplementary; exterior angle equals opposite interior angle.
  • Equal chords subtend equal arcs and equal central angles.
  • This topic guarantees 4–7 marks in DSE Paper 1 Section A(2) and Section B – master these skills!

Summary Checklist for Revision

  • Central angle = arc measure
  • Inscribed angle = half arc
  • Angle in semicircle = 90°
  • Equal chords ↔ equal arcs ↔ equal central angles
  • Cyclic quadrilateral: opposite angles supplementary
  • Cyclic quadrilateral: exterior angle = opposite interior
  • Prove using angle chasing