This article covers the essential skills of surface area and volume of 3D solids – a core topic in DSE Paper 1 Section A(2) and Section B worth 4–6 marks. You will learn the formulas for volume and surface area of common solids: prisms, cylinders, cones, spheres, and pyramids. You will also learn the length, area, and volume ratios for similar solids, and how to solve problems involving composite solids. The article includes step-by-step worked examples, DSE exam techniques, practice questions. These are essential skills that appear regularly in DSE papers.
By the end of this article, you should be able to:
3D mensuration appears every year in DSE Paper 1 Section A(2) and Section B. Questions may ask you to:
These are essential skills that also appear in real-world contexts like capacity, packaging, and construction.
3D mensuration questions often appear in Section A(2) as short-answer questions worth 3–4 marks, and in Section B as longer problems worth 5–6 marks.
For cones and pyramids, the volume is one-third of the corresponding prism/cylinder. Remember: \( V_{\text{cone}} = \frac{1}{3} V_{\text{cylinder}} \).
If two solids are similar, their corresponding lengths are proportional. Let the linear scale factor be \( k \) (ratio of corresponding lengths). Then:
This means if you double the dimensions (scale factor 2), the surface area becomes 4 times larger, and the volume becomes 8 times larger.
Question: Two similar cylinders have heights 5 cm and 15 cm. If the smaller cylinder has volume 200 cm³, find the volume of the larger cylinder.
Scale factor \( k = \frac{15}{5} = 3 \).
Volume ratio = \( k^3 = 27 \).
Volume of larger = \( 200 \times 27 = 5400 \) cm³.
Answer: 5400 cm³.
A composite solid is made up of two or more simple solids. To find the total volume or surface area:
Question: A solid is made of a cylinder of radius 4 cm and height 6 cm, with a hemisphere of the same radius on top. Find the total volume.
Volume of cylinder = \( \pi (4)^2 (6) = 96\pi \) cm³.
Volume of hemisphere = \( \frac{1}{2} \times \frac{4}{3}\pi (4)^3 = \frac{2}{3}\pi (64) = \frac{128\pi}{3} \) cm³.
Total volume = \( 96\pi + \frac{128\pi}{3} = \frac{288\pi + 128\pi}{3} = \frac{416\pi}{3} \) cm³.
Answer: \( \frac{416\pi}{3} \) cm³.
Question: A cone has radius 6 cm and height 8 cm. Find its volume.
\( V = \frac{1}{3} \pi r^2 h = \frac{1}{3} \pi (6)^2 (8) = \frac{1}{3} \pi \times 36 \times 8 = 96\pi \) cm³.
Answer: \( 96\pi \) cm³.
Question: Find the surface area of a sphere with radius 7 cm.
\( A = 4\pi r^2 = 4\pi (7)^2 = 4\pi \times 49 = 196\pi \) cm².
Answer: \( 196\pi \) cm².
Question: Two similar pyramids have volumes 54 cm³ and 432 cm³. Find the ratio of their corresponding heights.
Volume ratio = \( \frac{432}{54} = 8 \).
Since volume ratio = \( k^3 \), \( k = \sqrt[3]{8} = 2 \).
So the height ratio is 2:1.
Answer: 2:1.
Question 1 MC
Find the volume of a cylinder with radius 3 cm and height 10 cm.
A. \( 30\pi \) B. \( 60\pi \) C. \( 90\pi \) D. \( 120\pi \)
Question 2 MC
The surface area of a sphere is \( 144\pi \) cm². Find its radius.
A. \( 4 \) cm B. \( 6 \) cm C. \( 8 \) cm D. \( 12 \) cm
Question 3 Short Answer
A cone has radius 5 cm and slant height 13 cm. Find its total surface area.
Question 4 Short Answer
Two similar cylinders have heights 4 cm and 10 cm. If the smaller has volume 80 cm³, find the volume of the larger.
Question 5 MC
A solid is formed by a hemisphere on top of a cylinder of the same radius. If the radius is 3 cm and the cylinder height is 5 cm, what is the total volume?
A. \( 45\pi + 18\pi \) B. \( 45\pi + 9\pi \) C. \( 45\pi + 12\pi \) D. \( 45\pi + 6\pi \)
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An Exercise on Mensuration | Surface Area & Volume of 3D Solids