This article covers the essential skills of geometric sequences – a core topic in DSE Paper 1 Section A(1) and A(2) worth 4–6 marks. You will learn the definition of a geometric sequence, the general term formula
, the sum of first n terms formula, and how to solve application problems involving geometric means, compound interest, population growth, and more. The article includes step-by-step worked examples, DSE exam techniques, practice questions. These are essential skills that appear regularly in DSE papers.
By the end of this article, you should be able to:
Geometric sequences appear every year in DSE Paper 1 Section A(1) and A(2). Questions may ask you to:
These are essential skills that also extend to infinite series and exponential functions.
Geometric sequence questions often appear in Section A(1) as short-answer questions worth 2–3 marks, and in Section A(2) as longer problems worth 4–6 marks.
A geometric sequence (or geometric progression) is a sequence in which the ratio between consecutive terms is constant. This constant ratio is called the common ratio, denoted by \( r \).
The nth term of a geometric sequence is given by:
The sum of the first n terms of a geometric sequence is denoted by \( S_n \). The formula depends on the common ratio:
Sum of GP: \( S_n = \frac{a(1-r^n)}{1-r} \) (when \( r < 1 \)). If \( r > 1 \), use \( \frac{a(r^n-1)}{r-1} \) to avoid negative denominators.
Question: Find the sum of the first 8 terms of the geometric sequence \( 2, 6, 18, 54, \ldots \).
\( a = 2 \), \( r = \frac{6}{2} = 3 \), \( n = 8 \)
\( S_8 = \frac{2(3^8 - 1)}{3-1} = \frac{2(6561 - 1)}{2} = 6561 - 1 = 6560 \)
Answer: \( 6560 \)
Geometric means are numbers inserted between two given terms so that the resulting sequence is geometric. If \( k \) geometric means are inserted between \( a \) and \( b \), the common ratio is:
Question: Insert two geometric means between 2 and 54.
\( a = 2, b = 54, k = 2 \)
\( r = \left( \frac{54}{2} \right)^{\frac{1}{2+1}} = (27)^{1/3} = 3 \)
The terms are: \( 2, 6, 18, 54 \).
Answer: The means are \( 6, 18 \).
Geometric sequences are used to model situations with exponential growth or decay. Common examples include:
Question: A sum of $5000 is invested at 6% compound interest per annum. Find the total amount after 4 years.
Each year the amount is multiplied by \( 1 + 0.06 = 1.06 \).
So the amounts form a GP with \( a = 5000 \), \( r = 1.06 \), \( n = 4 \) (but after 4 years we need the 5th term? Wait: After 1 year: \( 5000 \times 1.06 \); after 2 years: \( 5000 \times 1.06^2 \); ... after 4 years: \( 5000 \times 1.06^4 \). That's the 5th term if starting from year 0, but we can just use \( T_5 \) with \( a = 5000 \), \( r = 1.06 \), \( n = 5 \)? Actually, the amount after n years is \( A_n = 5000 \times 1.06^n \).
For 4 years: \( A_4 = 5000 \times 1.06^4 \).
Compute: \( 1.06^4 = 1.26247696 \); \( 5000 \times 1.26247696 = 6312.3848 \).
Answer: Approximately $6312.38.
Question: The 2nd term of a geometric sequence is 12, and the 5th term is 96. Find the first term and the common ratio.
\( T_2 = ar = 12 \) ... (1)
\( T_5 = ar^4 = 96 \) ... (2)
Divide (2) by (1): \( \frac{ar^4}{ar} = \frac{96}{12} \) → \( r^3 = 8 \) → \( r = 2 \)
Substitute into (1): \( a \times 2 = 12 \) → \( a = 6 \)
Answer: \( a = 6, r = 2 \)
Question: Find the sum of the first 10 terms of the geometric sequence \( 1, -2, 4, -8, \ldots \).
\( a = 1, r = -2 \), \( n = 10 \)
\( S_{10} = \frac{1(1 - (-2)^{10})}{1 - (-2)} = \frac{1 - 1024}{1 + 2} = \frac{-1023}{3} = -341 \)
Answer: \( -341 \)
Question: Insert 3 geometric means between 5 and 405.
\( a = 5, b = 405, k = 3 \)
\( r = \left( \frac{405}{5} \right)^{\frac{1}{3+1}} = (81)^{1/4} = 3 \)
Terms: \( 5, 15, 45, 135, 405 \)
Answer: Means are \( 15, 45, 135 \).
Question 1 MC
Find the 7th term of the geometric sequence \( 2, 6, 18, 54, \ldots \).
A. \( 486 \) B. \( 1458 \) C. \( 4374 \) D. \( 13122 \)
Question 2 MC
What is the sum of the first 6 terms of \( 3, 6, 12, 24, \ldots \)?
A. \( 189 \) B. \( 189 \) C. \( 189 \) D. \( 189 \) (Wait, need correct values: Let's compute: \( S_6 = 3(2^6-1)/(2-1)=3(64-1)=189 \)). So answer A is 189.
Question 3 Short Answer
Find the general term of the geometric sequence \( 5, 10, 20, 40, \ldots \).
Question 4 Short Answer
How many terms are in the geometric sequence \( 3, 6, 12, \ldots, 768 \)?
Question 5 MC
If \( x, x+2, x+6 \) are consecutive terms of a geometric sequence, find \( x \).
A. \( 1 \) B. \( 2 \) C. \( 3 \) D. \( 4 \)
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An Exercise on Geometric Sequences | General Term & Sum of First n Terms