This article covers the essential skills of sum to infinity of geometric series – an advanced topic in DSE Paper 1 Section A(2) and Section B worth 4–6 marks. You will learn the convergence condition , the sum to infinity formula , how to convert recurring decimals to fractions using infinite series, and how to solve application problems such as bouncing balls, infinite processes, and financial models. The article includes step-by-step worked examples, DSE exam techniques, practice questions. These are high-level skills that can help you secure top marks.
By the end of this article, you should be able to:
Sum to infinity appears every year in DSE Paper 1 Section A(2) and Section B. Questions may ask you to:
These are high-level skills that can help you secure top marks in the exam.
Sum to infinity questions often appear in Section A(2) as short-answer questions worth 3–4 marks, and in Section B as longer problems worth 5–6 marks.
An infinite geometric series \( a + ar + ar^2 + ar^3 + \cdots \) converges (has a finite sum) only if:
If \( |r| \ge 1 \), the series diverges (does not have a finite sum).
When \( |r| < 1 \), the sum to infinity is given by:
This is derived from the finite sum formula by taking \( n \to \infty \), since \( r^n \to 0 \) when \( |r| < 1 \).
Question: Find the sum to infinity of \( 8 + 4 + 2 + 1 + \cdots \).
\( a = 8, r = \frac{1}{2} \)
\( |r| = \frac{1}{2} < 1 \), so it converges.
\( S_\infty = \frac{8}{1 - \frac{1}{2}} = \frac{8}{\frac{1}{2}} = 16 \)
Answer: \( 16 \)
A recurring decimal (e.g., \( 0.\overline{3} \)) can be expressed as an infinite geometric series and converted to a fraction.
Question: Convert \( 0.\overline{36} = 0.363636\ldots \) to a fraction.
\( 0.363636\ldots = 0.36 + 0.0036 + 0.000036 + \cdots \)
\( a = 0.36 = \frac{36}{100} \), \( r = \frac{0.0036}{0.36} = 0.01 = \frac{1}{100} \)
\( S_\infty = \frac{\frac{36}{100}}{1 - \frac{1}{100}} = \frac{\frac{36}{100}}{\frac{99}{100}} = \frac{36}{99} = \frac{4}{11} \)
Answer: \( \frac{4}{11} \)
Recurring decimals shortcut: For \( 0.\overline{ab} \), the fraction is \( \frac{ab}{99} \). For \( 0.\overline{abc} \), it's \( \frac{abc}{999} \), etc.
Sum to infinity is used to model situations involving infinite repetition, such as:
Question: A ball is dropped from a height of 10 m. After each bounce, it rebounds to \( \frac{3}{4} \) of its previous height. Find the total vertical distance traveled by the ball until it comes to rest.
Total distance = drop (10 m) + up and down bounces.
First bounce: up \( 10 \times \frac{3}{4} = 7.5 \), down 7.5, total 15.
Second bounce: up \( 7.5 \times \frac{3}{4} = 5.625 \), down 5.625, total 11.25.
So total after first drop = \( 10 + 2 \times \left( 7.5 + 5.625 + 4.21875 + \cdots \right) \).
The sum of bounces (up+down) after the first drop: first term \( 7.5 \), ratio \( \frac{3}{4} \), but each bounce has up and down, so total distance = \( 10 + 2 \times \frac{7.5}{1 - 0.75} = 10 + 2 \times 30 = 70 \) m.
Answer: 70 m.
Question: Find the sum to infinity of \( 12 - 6 + 3 - 1.5 + \cdots \).
\( a = 12, r = -\frac{1}{2} \). \( |r| = \frac{1}{2} < 1 \).
\( S_\infty = \frac{12}{1 - (-\frac{1}{2})} = \frac{12}{1.5} = 8 \).
Answer: \( 8 \).
Question: Express \( 2.\overline{5} = 2.555\ldots \) as a fraction.
\( 2.\overline{5} = 2 + 0.\overline{5} \).
\( 0.\overline{5} = \frac{5}{9} \) (using shortcut).
So \( 2.\overline{5} = 2 + \frac{5}{9} = \frac{18}{9} + \frac{5}{9} = \frac{23}{9} \).
Answer: \( \frac{23}{9} \).
Question: A person walks 20 m east, then turns around and walks 10 m west, then 5 m east, then 2.5 m west, and so on. What is the total distance from the starting point?
Net displacement east: \( 20 - 10 + 5 - 2.5 + \cdots \)
This is a GP with \( a = 20, r = -\frac{1}{2} \).
\( S_\infty = \frac{20}{1 - (-\frac{1}{2})} = \frac{20}{1.5} = \frac{40}{3} \approx 13.33 \) m.
Answer: \( \frac{40}{3} \) m east.
Question 1 MC
Which of the following geometric series converges?
A. \( 2 + 4 + 8 + 16 + \cdots \) B. \( 1 - 1 + 1 - 1 + \cdots \)
C. \( 9 + 3 + 1 + \frac{1}{3} + \cdots \) D. \( 5 + 10 + 20 + 40 + \cdots \)
Question 2 MC
The sum to infinity of \( 6 + 2 + \frac{2}{3} + \frac{2}{9} + \cdots \) is:
A. \( 8 \) B. \( 9 \) C. \( 10 \) D. \( 12 \)
Question 3 Short Answer
Convert \( 0.\overline{12} \) to a fraction.
Question 4 Short Answer
Find the sum to infinity of \( 48 + 24 + 12 + 6 + \cdots \).
Question 5 MC
A ball is dropped from 100 m and rebounds to half its previous height. What is the total distance traveled until rest?
A. \( 200 \) m B. \( 250 \) m C. \( 300 \) m D. \( 400 \) m
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An Exercise on Sum to Infinity | Convergence & Applications