Sum to Infinity | Convergence & Applications

Synopsis

This article covers the essential skills of sum to infinity of geometric series – an advanced topic in DSE Paper 1 Section A(2) and Section B worth 4–6 marks. You will learn the convergence condition , the sum to infinity formula , how to convert recurring decimals to fractions using infinite series, and how to solve application problems such as bouncing balls, infinite processes, and financial models. The article includes step-by-step worked examples, DSE exam techniques, practice questions. These are high-level skills that can help you secure top marks.


Learning Objectives

By the end of this article, you should be able to:

  • Identify the convergence condition \( |r| < 1 \) for an infinite geometric series.
  • Calculate the sum to infinity \( S_\infty \) using the formula.
  • Convert recurring decimals to fractions using infinite geometric series.
  • Solve problems involving infinite processes (e.g., bouncing balls, distance traveled).
  • Apply sum to infinity to financial and other real-world contexts.
  • Distinguish between finite and infinite sums and choose the correct formula.

1. Introduction:

Sum to infinity appears every year in DSE Paper 1 Section A(2) and Section B. Questions may ask you to:

  • Find the sum to infinity of a geometric series
  • Determine whether a series converges
  • Convert a recurring decimal to a fraction
  • Solve problems involving infinite geometric processes

These are high-level skills that can help you secure top marks in the exam.

DSE Exam Tip

Sum to infinity questions often appear in Section A(2) as short-answer questions worth 3–4 marks, and in Section B as longer problems worth 5–6 marks.

2. Convergence Condition

An infinite geometric series \( a + ar + ar^2 + ar^3 + \cdots \) converges (has a finite sum) only if:

$$ |r| < 1 \quad \text{or} \quad -1 < r < 1 $$

If \( |r| \ge 1 \), the series diverges (does not have a finite sum).

Examples

  • \( 1 + \frac{1}{2} + \frac{1}{4} + \frac{1}{8} + \cdots \) converges (\( r = \frac{1}{2} \))
  • \( 3 + 6 + 12 + 24 + \cdots \) diverges (\( r = 2 \))
  • \( 5 - 5 + 5 - 5 + \cdots \) diverges (\( r = -1 \))

3. Sum to Infinity Formula

When \( |r| < 1 \), the sum to infinity is given by:

$$ S_\infty = \frac{a}{1-r} $$

This is derived from the finite sum formula by taking \( n \to \infty \), since \( r^n \to 0 \) when \( |r| < 1 \).

Worked Example

Question: Find the sum to infinity of \( 8 + 4 + 2 + 1 + \cdots \).

Solution

\( a = 8, r = \frac{1}{2} \)

\( |r| = \frac{1}{2} < 1 \), so it converges.

\( S_\infty = \frac{8}{1 - \frac{1}{2}} = \frac{8}{\frac{1}{2}} = 16 \)

Answer: \( 16 \)

4. Converting Recurring Decimals to Fractions

A recurring decimal (e.g., \( 0.\overline{3} \)) can be expressed as an infinite geometric series and converted to a fraction.

Method

  1. Write the decimal as a sum of its repeating digits.
  2. Identify the first term \( a \) and the common ratio \( r \).
  3. Use the formula \( S_\infty = \frac{a}{1-r} \).

Worked Example

Question: Convert \( 0.\overline{36} = 0.363636\ldots \) to a fraction.

Solution

\( 0.363636\ldots = 0.36 + 0.0036 + 0.000036 + \cdots \)

\( a = 0.36 = \frac{36}{100} \), \( r = \frac{0.0036}{0.36} = 0.01 = \frac{1}{100} \)

\( S_\infty = \frac{\frac{36}{100}}{1 - \frac{1}{100}} = \frac{\frac{36}{100}}{\frac{99}{100}} = \frac{36}{99} = \frac{4}{11} \)

Answer: \( \frac{4}{11} \)

DSE Memory Aid

Recurring decimals shortcut: For \( 0.\overline{ab} \), the fraction is \( \frac{ab}{99} \). For \( 0.\overline{abc} \), it's \( \frac{abc}{999} \), etc.

5. Applications of Sum to Infinity

Sum to infinity is used to model situations involving infinite repetition, such as:

  • Bouncing balls: Total distance traveled
  • Infinite processes: Repeated actions with decreasing effect
  • Financial models: Perpetuities (infinite annuity) in finance
  • Fractal geometry: Infinite perimeter/area

Worked Example (Bouncing Ball)

Question: A ball is dropped from a height of 10 m. After each bounce, it rebounds to \( \frac{3}{4} \) of its previous height. Find the total vertical distance traveled by the ball until it comes to rest.

Solution

Total distance = drop (10 m) + up and down bounces.

First bounce: up \( 10 \times \frac{3}{4} = 7.5 \), down 7.5, total 15.

Second bounce: up \( 7.5 \times \frac{3}{4} = 5.625 \), down 5.625, total 11.25.

So total after first drop = \( 10 + 2 \times \left( 7.5 + 5.625 + 4.21875 + \cdots \right) \).

The sum of bounces (up+down) after the first drop: first term \( 7.5 \), ratio \( \frac{3}{4} \), but each bounce has up and down, so total distance = \( 10 + 2 \times \frac{7.5}{1 - 0.75} = 10 + 2 \times 30 = 70 \) m.

Answer: 70 m.

6. Worked Examples

Example 1: Basic Sum to Infinity

Question: Find the sum to infinity of \( 12 - 6 + 3 - 1.5 + \cdots \).

Solution

\( a = 12, r = -\frac{1}{2} \). \( |r| = \frac{1}{2} < 1 \).

\( S_\infty = \frac{12}{1 - (-\frac{1}{2})} = \frac{12}{1.5} = 8 \).

Answer: \( 8 \).

Example 2: Recurring Decimal

Question: Express \( 2.\overline{5} = 2.555\ldots \) as a fraction.

Solution

\( 2.\overline{5} = 2 + 0.\overline{5} \).

\( 0.\overline{5} = \frac{5}{9} \) (using shortcut).

So \( 2.\overline{5} = 2 + \frac{5}{9} = \frac{18}{9} + \frac{5}{9} = \frac{23}{9} \).

Answer: \( \frac{23}{9} \).

Example 3: Application

Question: A person walks 20 m east, then turns around and walks 10 m west, then 5 m east, then 2.5 m west, and so on. What is the total distance from the starting point?

Solution

Net displacement east: \( 20 - 10 + 5 - 2.5 + \cdots \)

This is a GP with \( a = 20, r = -\frac{1}{2} \).

\( S_\infty = \frac{20}{1 - (-\frac{1}{2})} = \frac{20}{1.5} = \frac{40}{3} \approx 13.33 \) m.

Answer: \( \frac{40}{3} \) m east.

7. DSE-Style Practice Questions

Section A(2) & Section B Style

Question 1 MC
Which of the following geometric series converges?
A. \( 2 + 4 + 8 + 16 + \cdots \)     B. \( 1 - 1 + 1 - 1 + \cdots \)
C. \( 9 + 3 + 1 + \frac{1}{3} + \cdots \)     D. \( 5 + 10 + 20 + 40 + \cdots \)

Question 2 MC
The sum to infinity of \( 6 + 2 + \frac{2}{3} + \frac{2}{9} + \cdots \) is:
A. \( 8 \)     B. \( 9 \)     C. \( 10 \)     D. \( 12 \)

Question 3 Short Answer
Convert \( 0.\overline{12} \) to a fraction.

Question 4 Short Answer
Find the sum to infinity of \( 48 + 24 + 12 + 6 + \cdots \).

Question 5 MC
A ball is dropped from 100 m and rebounds to half its previous height. What is the total distance traveled until rest?
A. \( 200 \) m     B. \( 250 \) m     C. \( 300 \) m     D. \( 400 \) m

8. Solutions with Explanations

Question 1: C. \( 9 + 3 + 1 + \frac{1}{3} + \cdots \)
Only C has \( |r| < 1 \) (\( r = \frac{1}{3} \)). A: \( r=2 \), B: \( r=-1 \), D: \( r=2 \).
Question 2: B. \( 9 \)
\( a = 6, r = \frac{1}{3} \), \( S_\infty = \frac{6}{1 - \frac{1}{3}} = \frac{6}{\frac{2}{3}} = 9 \).
Question 3: \( \frac{4}{33} \)
\( 0.\overline{12} = \frac{12}{99} = \frac{4}{33} \).
Question 4: \( 96 \)
\( a = 48, r = \frac{1}{2} \), \( S_\infty = \frac{48}{1 - \frac{1}{2}} = 96 \).
Question 5: C. \( 300 \) m
Total = \( 100 + 2 \times \frac{50}{1 - 0.5} = 100 + 2 \times 100 = 300 \) m.

9. Exercise

Click the following link to have
 An Exercise on Sum to Infinity | Convergence & Applications

Key Takeaways

What You Should Remember
  • Convergence condition: \( |r| < 1 \) for an infinite geometric series to have a finite sum.
  • Sum to infinity: \( S_\infty = \frac{a}{1-r} \).
  • Recurring decimals: Can be expressed as fractions using infinite geometric series.
  • Applications: Bouncing balls, infinite processes, financial perpetuities.
  • Check convergence: Always verify \( |r| < 1 \) before using the formula.
  • This topic guarantees 4–6 marks in DSE Paper 1 Section A(2) and Section B – master these skills!

Summary Checklist for Revision

  • Convergence condition: \( |r| < 1 \)
  • Sum to infinity: \( S_\infty = \frac{a}{1-r} \)
  • Recurring decimal conversion: \( 0.\overline{ab} = \frac{ab}{99} \)
  • Bouncing ball: total = \( h + 2 \times \frac{hr}{1-r} \)
  • Infinite series applications
  • Distinguish finite vs infinite sums
  • Check if \( r \) is within range